elastic多层嵌套聚合语句

elastic数据中存储了每个设备上传的抄表数据，需要对这些数据做分析展示
目的：展现每个小时的最大/最小/平均/和抄表值。
实现步骤：
1 先对抄表数据做时间聚合
2 然后对时间聚合的bucket做设备去重聚合
3 对设备去重的聚合再做top_hits聚合
经过这三个嵌套聚合能够获取每个时间段每个设备最接近整点的数据，然后在java程序中做最大/最小/平均的计算。但是这样操作会造成elastic形成很多的bukets,超过了最大的buckets数量，但是elastic又不允许改这些配置，如何能做到直接在elastic做这些最大/最小/平均的聚合？

现在的es的语句写法如下：
{
"size": 0,
"query": {
"bool": {
"must": [
{
"range": {
"ts": {
"from": 1612400400000,
"to": 1612404000000,
"include_lower": true,
"include_upper": true,
"boost": 1
}
}
}
],
"adjust_pure_negative": true,
"boost": 1
}
},
"_source": false,
"aggregations": {
"histName": {
"date_histogram": {
"field": "ts",
"fixed_interval": "1h",
"offset": -1800000,
"order": {
"_key": "asc"
},
"keyed": false,
"min_doc_count": 0,
"extended_bounds": {
"min": 1612400400000,
"max": 1612404000000
}
},
"aggregations": {
"dId": {
"terms": {
"field": "dId",
"size": 5000,
"min_doc_count": 1,
"shard_min_doc_count": 0,
"show_term_doc_count_error": false,
"order": [
{
"_count": "desc"
},
{
"_key": "asc"
}
]
},
"aggregations": {
"topHitsName": {
"top_hits": {
"from": 0,
"size": 1,
"version": false,
"seq_no_primary_term": false,
"explain": false,
"sort": [
{
"_script": {
"script": {
"source": "long s = doc['ts'].value.toInstant().toEpochMilli() % 3600000L;return (s >= 1800000L ? 3600000L - s : s);",
"lang": "painless"
},
"type": "number",
"order": "asc"
}
}
]
}
}
}
}
}
}
}
}